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Gronkowski is the AFC offensive player of the week

Gronkowski stays inbounds and breaks tackles from Gomes and Doughty on a long gain in Landover, Maryland

New England Patriots tight end Rob Gronkowski (87) stays inbounds and breaks tackles from Washington Redskins defensive back DeJon Gomes (24) and safety Reed Doughty (37) on a long gain during the first half of their NFL football game in Landover, Maryland December 11, 2011. REUTERS/Jonathan Ernst (UNITED STATES - Tags: SPORT FOOTBALL)

REUTERS

That epic catch, fall, and drag-a-pair of Redskins by Pats tight end Rob Gronkowski, part of a two-touchdown, 160-yard day, told us two things.

1. Gronkowski would be named the AFC offensive player of the week.

2. DeAngelo Hall, who proved that football really is a spectator sport, would not be named the NFL defensive player of the week.

Indeed, the man known simply as Gronk -- whom Redskins cornerback Josh Wilson described after Sunday’s game as a “gargoyle” -- is the AFC offensive player of the week.

Gronkwoski, who now holds the single-season touchdown record for tight ends with 15, had a 49-yard catch, a 50-yard catch, and a 37-yard touchdown reception against the Redskins.

And maybe the Pats will make it back to the Super Bowl if Gronkowski plays a little defense down the stretch, too. He could do at least as well as DeAngelo Hall.