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McDonald beats del Potro in Delray Beach Open

2019 Australian Open - Day 3

MELBOURNE, AUSTRALIA - JANUARY 16: Mackenzie Mcdonald of the United States plays a backhand in his second round match against Marin Cilic of Croatia during day three of the 2019 Australian Open at Melbourne Park on January 16, 2019 in Melbourne, Australia. (Photo by Julian Finney/Getty Images)

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DELRAY BEACH, Fla. -- American Mackenzie McDonald beat No. 1-seeded Juan Martin del Potro on Friday night in the quarterfinals of the Delray Beach Open, 6-4, 3-6, 7-6 (5).

McDonald, ranked 84th, advanced to his first ATP Tour semifinal. Del Potro was playing in his first event after missing four months because of a right knee injury.

No. 4 Steve Johnson of the United States squandered an early lead and lost to Radu Albot 1-6, 6-3, 7-6 (5). Albot will play McDonald on Saturday.

No. 2 John Isner hit 24 aces and won every service game to beat Adrian Mannarino 7-6 (2), 6-4. Isner improved his career record against the Frenchman to 7-1.

Isner’s opponent in the semifinals will be qualifier Dan Evans, ranked 148th, who swept No. 6 Andreas Seppi 6-4, 6-4.