Lamar Jackson named AFC Offensive Player of the Week


Lamar Jackson's heroic performance against the Cleveland Browns on Monday night earned him AFC Player of the Week honors, the Ravens announced on Wednesday.

This week marks the second time this year Jackson has won the award, as he was also named the conference's player of the week following the Ravens blowout over Cleveland in Week 1. Jackson won the award five times in 2019 during his MVP season.

Jackson's performance in Baltimore's 47-42 victory over the Browns is one Ravens fans won't forget anytime soon.

Through the first three quarters, Jackson gave the Browns defense fits with his legs, rather than his arm. By midway through the third quarter, the reigning MVP had already totaled over 100 rushing yards and two touchdowns on the ground.

Then, crazy happened.

Jackson unexpectedly rushed into the locker room at the beginning of the fourth quarter dealing with cramps, forcing backup Trace McSorley into action. Jackson missed two drives before heroically returning from the locker room for a fourth-and-5 play with the Ravens trailing by one, and found Marquise Brown for a 44-yard touchdown to regain the lead.

After the Browns tied the game at 42 with just over one minute remaining, Jackson led Baltimore down the field to set up a game-winning field goal from Justin Tucker just before time expired.

For the game, Jackson finished completing 11 of 17 passes for 163 yards and a touchdown, while carrying the ball nine times for 124 yards and two touchdowns.


Monday night was an epic performance from Jackson, as Baltimore moved to 8-5 on the season with three games to go.