Manuel Pellegrini’s winning plans don’t include English players
Manchester City, led by manager Manuel Pellegrini, possess the epitome of the new-look Premier League, no longer the English born-and-bred league of years past, as most of his best players, Yaya Toure, Vincent Kompany and Sergio Aguero among them, are foreign, coming to City for large price tags in hopes of dominating the BPL.
On Saturday, Arsenal blanked City 3-0, and the Sky Blues’ manager didn’t entertain the thought of playing any Englishmen. All 11 of his starters were from different countries, with Scott Sinclair, Micah Richards and James Milner coming off the bench.
“I repeat this was a special game but during the year I don’t look at the nationality of the players,” he said.
This offseason, the departures of Jack Rodwell, Gareth Barry and Joleon Lescott marked the squad’s under reliance on English-born footballers. Barry and Lescott were aging, unable to provide the high-caliber football that City desires from men who are brought into the team to win. Rodwell, only 23 years of age, has some promise, but once again, City wants midfielders taking the pitch to be capable of immediately providing first-class play.
In the end, City’s main focus is to have the best players in the PL, and with a heavy dosage of cash to acquire vital transfer targets, City has been catapulted to the top of the league table, right past inter-town, more celebrated rival Manchester United. Catering to the English representation wouldn’t have the reigning champions anywhere. Pellegrini recognizes that fact.
“I use the players I think are the best players to win that game. It doesn’t matter where they come from,” Pellegrini reiterated.
The real problem faced by City is not actually the lack of British presentation, but the way in which they acquire their marquee players from other countries. Along with Paris Saint-Germain and seven other clubs, UEFA penalized City for breaching the financial fair play (FFP) rules back in May because the team failed to live up to the “break even” test.