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Report: Mets sign Jay Bruce to three-year, $39 million contract

Divisional Round - New York Yankees v Cleveland Indians - Game One

CLEVELAND, OH - OCTOBER 05: Jay Bruce #32 of the Cleveland Indians hits a two-run home run during the fourth inning against the New York Yankees during game one of the American League Division Series at Progressive Field on October 5, 2017 in Cleveland, Ohio. (Photo by Gregory Shamus/Getty Images)

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ESPN’s Jerry Crasnick reports that free agent outfielder Jay Bruce is expected to sign with the Mets. According to Ken Rosenthal of The Athletic, it’s a three-year, $39 million contract. The deal is expected to be finalized tonight.

Bruce, 30, spent last season with the Mets and Indians, batting a composite .254/.324/.508 with 36 home runs and 101 RBI. In the ALDS, Bruce hit a pair of home runs in five games against the Yankees.

As a Met, over two half-seasons in 2016 and ’17, Bruce hit .245/.313/.482 with 37 home runs and 94 RBI in 635 plate appearances.

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